Remove '?' and '.' characters from source key names
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@ -1,14 +1,14 @@
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# Copyright 2019 Signal
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#
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# Permission is hereby granted, free of charge, to any person obtaining a copy of this software and
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# Permission is hereby granted, free of charge, to any person obtaining a copy of this software and
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# associated documentation files (the "Software"), to deal in the Software without restriction,
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# including without limitation the rights to use, copy, modify, merge, publish, distribute,
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# sublicense, and/or sell copies of the Software, and to permit persons to whom the Software is
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# furnished to do so, subject to the following conditions:
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#
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# The above copyright notice and this permission notice shall be included in all copies or
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#
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# The above copyright notice and this permission notice shall be included in all copies or
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# substantial portions of the Software.
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#
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#
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# THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR IMPLIED, INCLUDING BUT
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# NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY, FITNESS FOR A PARTICULAR PURPOSE AND
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# NONINFRINGEMENT. IN NO EVENT SHALL THE AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM,
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@ -21,7 +21,7 @@ module Weblate
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def self.get(source_text)
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source_text.nil? or source_text.empty? ? source_text
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: source_text.strip[0..150]
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.gsub(/([^\w\d\s\.\?\!]|\n)/, '')
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.gsub(/([^\w\d\s\!]|\n)/, '')
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.tr(' ', '_') << "_KEY"
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end
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end
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