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style!: Remove all mkdocs-material icon references
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@@ -78,7 +78,7 @@ One metric to determine the strength of a diceware passphrase is how much entrop
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<mn>2</mn>
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</msub>
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<mo form="prefix" stretchy="false">(</mo>
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<mtext>WordsInList</mtext>
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<mtext>WordsInList</mtext>
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<mo form="postfix" stretchy="false">)</mo>
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</mrow>
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</math> and the overall entropy of the passphrase is calculated as: <math>
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@@ -103,7 +103,7 @@ Therefore, each word in the aforementioned list results in ~12.9 bits of entropy
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<mn>2</mn>
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</msub>
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<mo form="prefix" stretchy="false">(</mo>
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<mn>7776</mn>
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<mn>7776</mn>
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<mo form="postfix" stretchy="false">)</mo>
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</mrow>
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</math>), and a seven word passphrase derived from it has ~90.47 bits of entropy (<math>
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@@ -122,10 +122,10 @@ Therefore, each word in the aforementioned list results in ~12.9 bits of entropy
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</math>).
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The [EFF's large word list](https://eff.org/files/2016/07/18/eff_large_wordlist.txt) contains 7776 unique words. To calculate the amount of possible passphrases, all we have to do is <math>
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<msup>
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<mtext>WordsInList</mtext>
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<mtext>WordsInPhrase</mtext>
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</msup>
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<msup>
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<mtext>WordsInList</mtext>
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<mtext>WordsInPhrase</mtext>
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</msup>
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</math>, or in our case, <math><msup><mn>7776</mn><mn>7</mn></msup></math>.
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Let's put all of this in perspective: A seven word passphrase using [EFF's large word list](https://eff.org/files/2016/07/18/eff_large_wordlist.txt) is one of ~1,719,070,799,748,422,500,000,000,000 possible passphrases.
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